1. The way the question is asked implies the two squares sum to the same area regardless of where you draw them. So let's make them equal size to simplify.
2. That means their shared edge splits the semicircle edge.
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Another edge case worth checking: the larger square touches both sides of the circle and is centered. In that case side of the larger square s is such that s^2 + (s/2)^2 = 8^2, so s = 16 / sqrt(5), and s^2 = 256/5.
But then how to figure out the size of the smaller square...
Aug 24, 2019 · 6:15 PM UTC


